cant figure this one out. just need to factor it 8r^3 - 27 ive got to (2r)^3 - 3^3
Last edited by siberianfog; Sep 22nd 2010 at 05:01 PM.
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Originally Posted by siberianfog cant figure this one out. just need to factor it 8r^3 - 27 ive got to (2r)^3 - 3^3 the factoring format for the difference (and sum) of two cubes should be in your text ... $\displaystyle a^3 - b^3 = (a-b)(a^2+ab+b^2)$
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