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Math Help - Help Solving Linear Eq

  1. #1
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    Help Solving Linear Eq

    I need help and instructions for solving this problem. If you could list the steps so I understand it would be appreciated.

    -7/8c +5.6 = -5/8c - 3.3
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  2. #2
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    ok i got that one now im stuck again x-1/2 +x-2/2 =3
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  3. #3
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    Quote Originally Posted by quarinteen View Post
    ok i got that one now im stuck again x-1/2 +x-2/2 =3
    Did you mean (x-1)/2 + (x-2)/2 = 3? Brackets are IMPORTANT.
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  4. #4
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    x - 1 over 2 + x - 2 over 2 = 3
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  5. #5
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    Is it:

    \dfrac{x-1}{2} + \dfrac{x-2}{2} = 3

    If it is, then you can multiply everything by 2 to get rid of the fractions.


    Or is it:

    \dfrac{\frac{x-1}{2 + x-2}}{2} = 3

    If it is, you can cancel out the +2 and minus 2 in the middle. Then multiply everything to get rid of the first fraction. Then multiply everything by x to get rid of the other fraction.

    EDIT: Nevermind about the x's and c's.
    Last edited by Educated; September 21st 2010 at 08:29 PM. Reason: Second possibility.
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  6. #6
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    its the top one. I dont know how to do the signs on the computer. Can you write out the steps for me so I understand it. Thank you very much.
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  7. #7
    Senior Member Educated's Avatar
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    It is called LaTeX

    Here's a link to the tutorial: LaTeX tutorial


    I have told you how to solve it. Multiply everything by 2 to get rid of the fractions. After that, group similar terms and solve for x. Can you solve x yourself?
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  8. #8
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    I multiplied every thing by 2 i get a answer different then the book gives as an answer. I get

    2x -2 + 2x - 4 = 6
    4x - 6 = 3
    4x = 9
    x = 9 / 4

    but the answer is 9/2
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  9. #9
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    \dfrac{x-1}{2} + \dfrac{x-2}{2} = 3

    OK here's a hint: When you multiply the fraction by its denominator, in this case it is 2, you effectively cancel it out.

    Example:

    \dfrac{a+b}{c} \times c = a+b

    Do you get it?
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  10. #10
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    No i don't get it. Can you please put out the steps. I am not in school I haven't been for a while. I was attempting to help a friend got to this problem and its bugging me. I just want to know the steps so I can understand. Unfortunately to say I graduated college already im in information security and never use math. My math skills have completely disappeared. Like I said this is just bugging the living daylights out of me...
    Last edited by mr fantastic; September 29th 2010 at 05:04 AM.
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  11. #11
    Senior Member Educated's Avatar
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    Here's a way that I hope you understand:

    \dfrac{x-1}{2} is the same as (x-1) \div 2 Correct?

    We multiply it by 2. This will make it become: (x-1) \div 2 \times 2

    Now can you see how they cancel eachother out? The multiply by 2 undoes the divided by 2, thus leaving only x-1.

    Do you know how to solve it now?
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