My problem is:
Solve for x: ax + b = bx - a
I found a similar problem in the book, and wondered if I'm on the right track or not.
I rewrote:
ax - bx = -a - b
x(a - b) = -a - b
x = -1 ?Code:x = -a – b ------- a – b
I guess because each letter is only equal to 1 my only possible answer is then 1? Is that how we get this answer? I'm only guessing...
I thought it was supposed to equal a number not the resulting fraction. It's a little confusing anyway. I'm not sure why I was trying to make x equal a number .
Can you please explain how this one equals 1 and the other one results to a fraction?
ax + b = bx + a
Thanks again! Just trying to understand this, so hopefully I'll retain it.
ok, so there were no instructions that said must be a number. it said we should simply solve for in terms of the other letters.
Now recall, a fraction is equal to 1 if the numerator and denomenator are equal--and of course the denominator can't be zero. We get -1 if the numerator is the negative of the denominator, which was the case in the example i choose that we would need to get -1.
Now on to the next question:
..........get all the 's on one side
........now factor out the common
.......now divide both sides by
we have a number divided by itself, provided we will get 1
So,