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Math Help - Solving f(x) equation with a fraction

  1. #1
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    Solving f(x) equation with a fraction

    I have this problem:

    f(x) = 2X^2 + 6x - 1
    find f(1/2)

    The book says the answer is 5/2.

    I can't seem to get this. I am missing something.

    f(1/2) = 2(1/2)^2 + 6(1/2) - 1

    2(1/4) + 6/2 - 1
    2/4 + 6/2 - 1
    This is where I am screwing up. I don't know the proper way to proceed.

    EDIT I think I got it, does this look legit?

    1/2 + 6/2 - 2/2

    7/2 - 2/2

    5/2
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  2. #2
    Senior Member yeKciM's Avatar
    Joined
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    Quote Originally Posted by mrnemo View Post
    I have this problem:

    f(x) = 2X^2 + 6x - 1
    find f(1/2)

    The book says the answer is 5/2.

    I can't seem to get this. I am missing something.

    f(1/2) = 2(1/2)^2 + 6(1/2) - 1

    2(1/4) + 6/2 - 1
    2/4 + 6/2 - 1
    This is where I am screwing up. I don't know the proper way to proceed.
    I tried 1/4 + 2 and that doesn't work...

    you just made mistake with  \frac {2}{4} = \frac {1}{2} .... it's not  \frac {1}{4}

     \frac {2}{4} + \frac {6}{2} - 1 = \frac {1}{2} +3 - 1 = \frac {1}{2} +2 = \frac {1+4 }{2} = \frac {5}{2}


    Edit: yes you did correct now
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  3. #3
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    Thanks. Yours is definitely cleaner. I appreciate the help.
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