# Need help please Algebra 2 questions

• Sep 19th 2010, 11:47 AM
xxsoccerforeverxx
Need help please Algebra 2 questions
1). Graph the function of y=square root of x-2 end of square root +5 which point lies on the graph?
2). y= square root of x+6 end of square root +2 which point lies on the graph?
Thank you!!
• Sep 19th 2010, 01:19 PM
skeeter
Quote:

Originally Posted by xxsoccerforeverxx
1). Graph the function of y=square root of x-2 end of square root +5 which point lies on the graph?
2). y= square root of x+6 end of square root +2 which point lies on the graph?
Thank you!!

just guessing here ... is this what you mean?

$y = \sqrt{x-2} + 5$
• Sep 19th 2010, 01:27 PM
xxsoccerforeverxx
yes, thats what I mean
• Sep 19th 2010, 01:34 PM
skeeter
the graph of $y = \sqrt{x-2} + 5$ is a transformation of the parent function $y = \sqrt{x}$ ... do you understand how the parent graph changes with each transformation?
• Sep 19th 2010, 01:47 PM
pickslides
Quote:

Originally Posted by xxsoccerforeverxx
1). Graph the function of y=square root of x-2 end of square root +5 which point lies on the graph?

$\displystyle y = \sqrt{x-2}+5$ lies on which graph?
• Sep 19th 2010, 02:35 PM
xxsoccerforeverxx
You have to graph it then see which point lies on the graph, but I don't know how.
• Sep 19th 2010, 02:55 PM
skeeter
Quote:

Originally Posted by xxsoccerforeverxx
You have to graph it then see which point lies on the graph, but I don't know how.

did you know that you can sub in the x-coordinate and see if it works out to the y-coordinate?

specifically ... (I'm making this up since you provided no information about specific points in your OP) ... say you need to check the point $(2,5)$

$y = \sqrt{x-2} + 5$

sub in $x = 2$

$y = \sqrt{2-2} + 5 = 0 + 5 = 5$

now you can say the point $(2,5)$ lies on the curve $y = \sqrt{x-2} + 5$
• Sep 19th 2010, 03:05 PM
pickslides
Many points lie on this graph, how many are you after?

Or are you trying to find the domain and range?
• Sep 19th 2010, 03:27 PM
xxsoccerforeverxx
just two points didn't say domain and range
• Sep 19th 2010, 03:38 PM
skeeter
Quote:

Originally Posted by xxsoccerforeverxx
just two points didn't say domain and range