what does resticted value mean?

**lostone** · June 5th 2007, 06:42 PM

Please help me with this question

State the restricted values of x for 6x-5
2x(x+4)

I really am lost on this....

thanks

**ThePerfectHacker** · June 5th 2007, 06:43 PM

Originally Posted by lostone

Please help me with this question

State the restricted values of x for 6x-5
2x(x+4)

I really am lost on this....

thanks

It is when the denominator is zero:

$2x(x+4)=0$

Make each factors zero and solve:
$2x=0 \mbox{ and }x+4=0$

**lostone** · June 5th 2007, 06:51 PM

So that means the answer is zero?

Originally Posted by ThePerfectHacker

It is when the denominator is zero:

$2x(x+4)=0$

Make each factors zero and solve:
$2x=0 \mbox{ and }x+4=0$

**ThePerfectHacker** · June 5th 2007, 06:52 PM

Originally Posted by lostone

So that means the answer is zero?

No!

We need to do both factors.

1) $2x=0 \Rightarrow x=0$
2) $x+4=0 \Rightarrow x=-4$ .

Thus,
$x=0,-4$ are the two restricted values.

**lostone** · June 5th 2007, 07:05 PM

Why would the question be writen with only term "x" if it is used to make 2 different numbers = 0? Like y would it not b writen 6x-5
2x(y+4)

X= 0
y= -4 instead of "x" = 2 different numbers.

**ThePerfectHacker** · June 5th 2007, 07:09 PM

Originally Posted by lostone

Why would the question be writen with only term "x" if it is used to make 2 different numbers = 0? Like y would it not b writen 6x-5
2x(y+4)

X= 0
y= -4 instead of "x" = 2 different numbers.

There are two possible values for $x$ .

For example,
Solve: $x^2-1=0$ .

If you factor,
$(x+1)(x-1)=0$
Making factors equal to zero we find that,
$x=-1$ or $x=1$ .

Those are the two possible values for x which solve this.

Same here, it does not mean that there has to be only one value for x there can be two (or more).

**lostone** · June 5th 2007, 07:16 PM

so there is no rule that x has to equal 1 number....why would they write it that way? Just to make it more difficult?

Originally Posted by ThePerfectHacker

No!

We need to do both factors.

1) $2x=0 \Rightarrow x=0$
2) $x+4=0 \Rightarrow x=-4$ .

Thus,
$x=0,-4$ are the two restricted values.

Originally Posted by ThePerfectHacker

There are two possible values for $x$ .

For example,
Solve: $x^2-1=0$ .

If you factor,
$(x+1)(x-1)=0$
Making factors equal to zero we find that,
$x=-1$ or $x=1$ .

Those are the two possible values for x which solve this.

Same here, it does not mean that there has to be only one value for x there can be two (or more).

**ThePerfectHacker** · June 5th 2007, 07:26 PM

Originally Posted by lostone

so there is no rule that x has to equal 1 number....why would they write it that way?

No there is not rule. Just write
$x = 0$ or $x=-4$ .
That is it.

Just to make it more difficult?

Stop complaining.

**lostone** · June 5th 2007, 07:45 PM

I really appreciate the help!!! and I'm not complaining just having a hard time that's all.....Thank-you again!!!

Originally Posted by ThePerfectHacker

No there is not rule. Just write
$x = 0$ or $x=-4$ .
That is it.

Stop complaining.

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