Please help me with this question

State the restricted values of x for6x-5

2x(x+4)

I really am lost on this....

thanks

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- Jun 5th 2007, 06:42 PM #1

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- Jun 5th 2007, 06:43 PM #2

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- Jun 5th 2007, 06:51 PM #3

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- Jun 5th 2007, 06:52 PM #4

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- Jun 5th 2007, 07:05 PM #5

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- Jun 5th 2007, 07:09 PM #6

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There are two possible values for $\displaystyle x$.

For example,

Solve: $\displaystyle x^2-1=0$.

If you factor,

$\displaystyle (x+1)(x-1)=0$

Making factors equal to zero we find that,

$\displaystyle x=-1$ or $\displaystyle x=1$.

Those are the two possible values for x which solve this.

Same here, it does not mean that there has to be only one value for x there can be two (or more).

- Jun 5th 2007, 07:16 PM #7

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- Jun 5th 2007, 07:26 PM #8

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- Jun 5th 2007, 07:45 PM #9

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