Is that right? $\displaystyle \frac{3-x}{-10} = -\frac{3-x}{10}$
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Yes. This is also correct. $\displaystyle \dfrac{3-x}{-10}=\dfrac{x-3}{10}$. Do you understand why?
Yes. Thanks
Another question. Is this right? $\displaystyle (\dfrac{x-1}{2})^{2} = \dfrac{x-1}{2} * \dfrac{x-1}{2} = \dfrac{x^{2}-2x+1}{4}$
Originally Posted by klik11 Another question. Is this right? $\displaystyle (\dfrac{x-1}{2})^{2} = \dfrac{x-1}{2} * \dfrac{x-1}{2} = \dfrac{x^{2}-2x+1}{4}$ Yes that is correct.
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