I'm kind of struggling with factoring when encountering multiple exponents. Can someone please explain the steps to factor the following?

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- September 17th 2010, 06:59 AMsoftwareguyHow to factor with multiple exponents?
I'm kind of struggling with factoring when encountering multiple exponents. Can someone please explain the steps to factor the following?

- September 17th 2010, 07:04 AMe^(i*pi)
You need to find a common factor - when there are multiple exponents on the same base then the

**lowest**exponent is a factor of all of them - in this case is a factor (and so is 4). In this case you will get a quadratic once you take out the factors - you should check if it factorises to (which it does in this case)

My answer is in a spoiler below

__Spoiler__: - September 17th 2010, 08:13 AMsoftwareguy
I don't get it. Can you please break it down step by step as to how you got the 5 and -2?

- September 17th 2010, 08:25 AMe^(i*pi)
Do you understand that you can factor initally?

This gives:

However, the can also be factorised to give the answer of - September 17th 2010, 08:52 AMsoftwareguy
Ah, ok, I got it. But what about when there is no exponent or x on the last number, such as:

I know it is:

(x+2)(x-2)(x+4)(x-4)

But I want to know a simple way of break it down step by step to arrive at that. That is what I'm struggling with. Thanks. - September 17th 2010, 08:57 AMmasters
- September 17th 2010, 09:50 AMsoftwareguy
Thanks, that helps.

One other thing. Is there any "trick" to more quickly figuring this out? For example, lets say you have a larger last number, such as:

I'm struggling how to come up with the answer for this one. - September 17th 2010, 10:08 AMe^(i*pi)
That is a tough one, but that can't be right because mind you it will be close so I will try 25 which is also a factor of 900:

. Now to check if which works.

Hence

Yet these are both the difference of two squares: