Express $\displaystyle \frac{3+h}{h} \times \frac{4h^2}{9-h^2}$ as a single fraction in its simplest form.
If you multiply two fractions, you multiply the numerators and the denominators.
$\displaystyle \frac{3+h}{h} * \frac{4h^2}{9-h^2}$
$\displaystyle \frac{(3+h)*(4h^2)}{h*(9-h^2)}$
$\displaystyle \frac{12h^2+4h^3}{9h-h^3}$
You will still need to simplify this and I'd like to encourage you to try that, but if you can't figure it out, feel free to post that.
Edit: Ah well, never mind xD