I am having a problem solving is 4 a solution to 1/2 (y-2)+2= 3/8 (3y-4) not sure where to begin.
Maybe expand these brackets and group some like terms to solve.
Here's a kick start...
$\displaystyle \frac{1}{2}(y-2)+2 = \frac{3}{8}(3y-4)$
$\displaystyle \frac{y}{2}-1+2 = \frac{9y}{8}-\frac{12}{8}$
$\displaystyle \frac{y}{2}+1 = \frac{9y}{8}-\frac{12}{8}$
Or if you only need to know if 4 is a solution then substitute it into both LHS and RHS of the equation. Do you get the same result?