solving Equations with fractions

**fc1123** · September 15th 2010, 02:11 PM

I am having a problem solving is 4 a solution to 1/2 (y-2)+2= 3/8 (3y-4) not sure where to begin.

**pickslides** · September 15th 2010, 02:22 PM

Maybe expand these brackets and group some like terms to solve.

Here's a kick start...

$\frac{1}{2}(y-2)+2 = \frac{3}{8}(3y-4)$

$\frac{y}{2}-1+2 = \frac{9y}{8}-\frac{12}{8}$

$\frac{y}{2}+1 = \frac{9y}{8}-\frac{12}{8}$

Or if you only need to know if 4 is a solution then substitute it into both LHS and RHS of the equation. Do you get the same result?

**skeeter** · September 15th 2010, 02:36 PM

multiply both sides of the equation by 8 to clear the fractions ...

$8\left[\frac{1}{2}(y-2)+2\right] = 8\left[\frac{3}{8}(3y-4)\right]$

$4(y-2)+16 = 3(3y-4)$

take it from there? ...

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