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Math Help - Word Problems involving percents.

  1. #1
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    Word Problems involving percents.

    Here is my problem:


    What number increased by 6% of itself equals 2650?

    I've gotton to the point of: 1.06x=2650 0VER 1.06(in a fraction). But I'm stuck on what to do next. Hellllp.
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  2. #2
    is up to his old tricks again! Jhevon's Avatar
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    Quote Originally Posted by Going Postal View Post
    Here is my problem:


    What number increased by 6% of itself equals 2650?

    I've gotton to the point of: 1.06x=2650 0VER 1.06(in a fraction). But I'm stuck on what to do next. Hellllp.
    i don't see your problem

    Let the number be x

    x + 6 \% x = 2650

    \Rightarrow x + 0.06x = 2650

    \Rightarrow 1.06x = 2650 .......Now divide both sides by 1.06

    \Rightarrow x = \frac {2650}{1.06}

    \Rightarrow x = 2500


    Note that "percentage" is just a fancy word for "over 100." so 6% means 6/100, 25% means 25/100. also note that "of" means "multiply." so 6% of x means 6/100 * x = 0.06 * x = 0.06x. and that's what we added to x
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  3. #3
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    Well, let's call the number you're looking for x, as you did.

    Then, notice that if you take x and "add it to 6% of itself", you just get

     x + \{ \textrm{6\% of }x\} = x + 0.06 \times x = 1.06 \times x

    So your problem is just this:

    1.06 \times x = 2650

    so that x = \frac{2650}{1.06} = 2500

    (Edit: My apologies, Jhevon was there first)
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  4. #4
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    Ahhh. Mental errors. Might not would happen if my mom would get off my case. Thanks to both of you.
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