(3xy^-2)^2(-2x^-4y)^3 / (x^-3y^2)^-3
I tried to check problem and of course it says my answer is wrong, but I can't figure out why!
I got:
-72y^5/x^19
(3xy^-2)^2(-2x^-4y)^3 / (x^-3y^2)^-3
I tried to check problem and of course it says my answer is wrong, but I can't figure out why!
I got:
-72y^5/x^19
Hmm I get what you get.
$\displaystyle \dfrac{(3xy^{-2})^2(-2x^{-4}y)^3}{(x^{-3}y^2)^{-3}} =(3xy^{-2})^2(-2x^{-4}y)^3(x^{-3}y^2)^3 $
$\displaystyle =(9x^2y^{-4})(-8x^{-12}y^3)(x^{-9}y^{6})=(9)(-8)x^{2-12-9}y^{-4+3+6}=\dfrac{-72y^5}{x^{19}}$
What does your book say? (Or is it that your solution is getting rejected by an automatic checker? I have not worked with those, but perhaps it has to do with typesetting or putting the answer in a form the computer will recognize.)
Thank you Undefined and Educated. Yes the way that undefined wrote it out was correct. I tried the [tex] formatting but it came out funky. I was checking it on mathway.com. And it came out with something like:
$\displaystyle 9y^2/{x^19}$.
Again thanks for the replies, I knew I was right!
Best way to learn LaTeX is to read the tutorial.
LaTeX Tutorial
I find that Wolfram|Alpha is a good maths computational website. Just remember to use brackets.