1. ## ratio of apples

Dear Sir
I would be grateful if you can help me to solve the the below questions
thanks
Kingsman

At the party, each child had either 1 apple or 2 apples. If the ratio of the number of children to the number of apples was 5: 8, what fraction of the children had 2 apples each?

2. Originally Posted by kingman
Dear Sir
I would be grateful if you can help me to solve the the below questions
thanks
Kingsman

At the party, each child had either 1 apple or 2 apples. If the ratio of the number of children to the number of apples was 5: 8, what fraction of the children had 2 apples each?
2 + 2 + 2 + 1 + 1 = 8

3. Dear Sir,
Can you show me how to do this question algebraically.
Thanks

4. Hello, kingman!

At the party, each child had either 1 apple or 2 apples.
If the ratio of the number of children to the number of apples was 5: 8,
what fraction of the children had 2 apples each?

Let $\displaystyle \,A$ = number of children with 1 apple.
Let $\displaystyle \,B$ = number of children with 2 apples.

Then there were: .$\displaystyle A+B$ children.

And there were: .$\displaystyle A + 2B$ apples.

. . We want the fraction: .$\displaystyle \dfrac{B}{A+B}$

We are told that: .$\displaystyle \dfrac{\text{children}}{\text{apples}} \:=\:\dfrac{5}{8}$

. . . .So we have: . $\displaystyle \dfrac{A+B}{A+2B} \:=\:\dfrac{5}{8}$

which simplifies to: . . . $\displaystyle \dfrac{A}{B} \;=\;\dfrac{2}{3}$

Add 1 to both sides: .$\displaystyle \dfrac{A}{B} + 1 \;=\;\dfrac{2}{3} + 1 \quad\Rightarrow\quad \dfrac{A+B}{B} \;=\;\dfrac{5}{3}$

. . Therefore: .$\displaystyle \dfrac{B}{A+B} \;=\;\dfrac{3}{5}$

5. Dear Soroban.
You are a fantastic problem solver and I love your approach to the problem very much.Crystal Clear!
Thousand Thanks
Kingman

6. Dear Sir,
Can this problem be solved by looking at the remainder when the number of apples ( 8x ) is divided by the number of children ( 5x)
Thanks
Kingman