Page 2 of 2 FirstFirst 12
Results 16 to 23 of 23

Math Help - Having Trouble Solving An Algebra Equation

  1. #16
    Senior Member tukeywilliams's Avatar
    Joined
    Mar 2007
    Posts
    307
    The answer can either be  -1.37 or  1.37 . Thats what the  \pm sign means.  1.37 is approximately the square root of  1.89 .
    Follow Math Help Forum on Facebook and Google+

  2. #17
    Newbie RyanCouture's Avatar
    Joined
    Jun 2007
    Posts
    18
    lol i hate to keep bothering you but could you help me with one last one?

    im reviewing for an exam here and this stuff has completely flown out of my head.

    7x^3+23x+6=0

    now for this i would use the zero product property right?

    could you please give me one last demonstration?

    thanks budd
    Follow Math Help Forum on Facebook and Google+

  3. #18
    Senior Member tukeywilliams's Avatar
    Joined
    Mar 2007
    Posts
    307
    So the equation is:  7x^{3} + 23x + 6 = 0

    You are right that you would use the zero product property to solve for  x . I dont think you can factor this. You sure you copied it down correctly?
    Follow Math Help Forum on Facebook and Google+

  4. #19
    Newbie RyanCouture's Avatar
    Joined
    Jun 2007
    Posts
    18
    yep

    just says solve
    Follow Math Help Forum on Facebook and Google+

  5. #20
    Senior Member tukeywilliams's Avatar
    Joined
    Mar 2007
    Posts
    307
    Its wouldnt happen to be  7x^{2} + 23x + 6 = 0 ?

    I changed the cubed term to a squared term.
    Follow Math Help Forum on Facebook and Google+

  6. #21
    Newbie RyanCouture's Avatar
    Joined
    Jun 2007
    Posts
    18
    nope lol

    but like i said a couple of posts earlier, i would not doubt if it was a typo as well.

    are you saying it cant be done with x cubed?

    if not, then yeah lets just do it squared
    Follow Math Help Forum on Facebook and Google+

  7. #22
    Senior Member tukeywilliams's Avatar
    Joined
    Mar 2007
    Posts
    307
    Yeah, its probably a typo. I even plugged in the equation into Maple, and the answer was very long and complicated. So I bet it is a typo.

    So if the equation is  7x^{2} + 23x + 6 = 0 then you have to factor it.


    You get:  (x+3)(7x+2) = 0

    Using the zero product property,  x + 3 = 0 or  7x+2 = 0 . Then  x = -3 \; \text{or} \; x = -\frac{2}{7} .

    You could also solve this using the quadratic formula. But this is easier.
    Follow Math Help Forum on Facebook and Google+

  8. #23
    Newbie RyanCouture's Avatar
    Joined
    Jun 2007
    Posts
    18
    alright great thanks alot
    Follow Math Help Forum on Facebook and Google+

Page 2 of 2 FirstFirst 12

Similar Math Help Forum Discussions

  1. Having Trouble Solving Logarithmic Equation
    Posted in the Pre-Calculus Forum
    Replies: 2
    Last Post: October 17th 2011, 04:40 PM
  2. Having trouble solving this equation
    Posted in the Algebra Forum
    Replies: 4
    Last Post: December 5th 2010, 08:19 AM
  3. Solving Vector Algebra Equation
    Posted in the Algebra Forum
    Replies: 1
    Last Post: August 12th 2009, 01:35 PM
  4. Replies: 45
    Last Post: August 5th 2009, 11:31 PM
  5. quick algebra solving equation problem
    Posted in the Algebra Forum
    Replies: 1
    Last Post: February 9th 2007, 04:11 PM

Search Tags


/mathhelpforum @mathhelpforum