# Thread: Having Trouble Solving An Algebra Equation

1. The answer can either be $-1.37$ or $1.37$. Thats what the $\pm$ sign means. $1.37$ is approximately the square root of $1.89$.

2. lol i hate to keep bothering you but could you help me with one last one?

im reviewing for an exam here and this stuff has completely flown out of my head.

7x^3+23x+6=0

now for this i would use the zero product property right?

could you please give me one last demonstration?

thanks budd

3. So the equation is: $7x^{3} + 23x + 6 = 0$

You are right that you would use the zero product property to solve for $x$. I dont think you can factor this. You sure you copied it down correctly?

4. yep

just says solve

5. Its wouldnt happen to be $7x^{2} + 23x + 6 = 0$?

I changed the cubed term to a squared term.

6. nope lol

but like i said a couple of posts earlier, i would not doubt if it was a typo as well.

are you saying it cant be done with x cubed?

if not, then yeah lets just do it squared

7. Yeah, its probably a typo. I even plugged in the equation into Maple, and the answer was very long and complicated. So I bet it is a typo.

So if the equation is $7x^{2} + 23x + 6 = 0$ then you have to factor it.

You get: $(x+3)(7x+2) = 0$

Using the zero product property, $x + 3 = 0$ or $7x+2 = 0$. Then $x = -3 \; \text{or} \; x = -\frac{2}{7}$.

You could also solve this using the quadratic formula. But this is easier.

8. alright great thanks alot

Page 2 of 2 First 12