but im not sure how i would solve this (question in attachment!)

could someone please point me in the right direction to solving this question!?!

Attachment 18912

Thanks!!

Printable View

- Sep 13th 2010, 06:22 AMandyboy179not sure if it is algebra...
but im not sure how i would solve this (question in attachment!)

could someone please point me in the right direction to solving this question!?!

Attachment 18912

Thanks!! - Sep 13th 2010, 06:36 AMyeKciM
- Sep 13th 2010, 06:40 AMandyboy179
if i multiply all by 3x-7 it would be, 6x+7/3x-7=2? then what would i do?

- Sep 13th 2010, 06:40 AMSudharaka
- Sep 13th 2010, 06:42 AMandyboy179
so it would be, 6x+7/ 9x-49=2 then 4x+7/ 7x-49=2???

- Sep 13th 2010, 06:47 AMyeKciM
- Sep 13th 2010, 06:50 AMandyboy179
i really don't understand this!! could i do box method with 2x+1 and 3x-7? to get 6x^2-x-6?

- Sep 13th 2010, 07:00 AMyeKciM
let's look at this this way ...

multiply both sides of equation with 2 and you will have

do you see that nothing is changed ?

now with fractions ....

because of that under fraction is 2 (can be anything) to lose that fraction you multiply both sides with that whatever is under fraction ....

in this case multiply with 2

- Sep 13th 2010, 07:07 AMandyboy179
i kinda understand now. you say multiply both sides with 2 so how would i do 2x+1x2? and 3x-7x2?

- Sep 13th 2010, 07:12 AMyeKciM
you don't multiply by two in your problem there... i just do that with my example to show you that nothing changes if you multiply both sides (or add or divide or ... ) Whatever is "down" in fraction (can't figure out how to write it on English :D) you multiply both sides with THAT :D in your case it's 3x-7 :D

so you will be free of the fraction :D

P.S. when multiplying fraction with number you don't multiply down expression :D

but only if you are multiplying fraction with fraction ...

- Sep 13th 2010, 07:14 AMandyboy179
OHHH so would it be 6x^2 - 10x -6?

- Sep 13th 2010, 07:20 AMyeKciM
- Sep 13th 2010, 07:22 AMandyboy179
would the answer be 2.3?? don't worry i can understand the english but im just finding it hard to pick up how to do these sort of questions!

- Sep 13th 2010, 07:32 AMyeKciM
you have solution in my first post :D (#2)

it's not problem for you with English ... it's mine :D:D:D

P.S. you need to get familiar with basic operations with fractions, and on fractions (as multiplying , divide, add , subtract .... ) so you will not have problem piking up stuff like this :D