This is a quadratic equation: Depending on , it may have zero, one or two solutions, which are given by the standard formula for the roots of a quadratic equation.
I'm working on a calculus problem, but I'm stuck with something algebraically:
I'm trying to solve for y so I can graph it. I started by factoring y:
But that's as far as I can get. If I divide both sides by y, that still leaves me with x/y = y-7. The extra y on the right side of the equation is stumping me and I can't figure out how to get rid of it. Any ideas?
My issue is that I need to find where the two lines intersect (In Quadrant II)
x = y^2-7y
x = 2y-y^2
After about 30 minutes of brute forcing it, I figured out that that they intersect at (-11.25,4.5) but does an easier method exist mathematically for determining that?