My chemistry text gave me this equation and the algebra I'm using doesn't give me the right answer. Can someone show me the steps to get to the right answer? [(.449)(400)(32.8-20)] + [(4.184)(1000)(32.8 - x)] = 0 solve for x Thanks
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Originally Posted by DannyMath [(.449)(400)(32.8-20)] + [(4.184)(1000)(32.8 - x)] = 0 solve for x Thanks [(.449)(400)(32.8-20)] + [(4.184)(1000)(32.8 - x)] = 0 (4.184)(1000)(32.8 - x) = -(.449)(400)(32.8-20) (32.8 - x) = -[(.449)(400)(32.8-20)]/[(4.184)(1000)] - x = -[(.449)(400)(32.8-20)]/[(4.184)(1000)]-32.8 x = [(.449)(400)(32.8-20)]/[(4.184)(1000)]+32.8