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Math Help - solve for x? help me complete the problem? :D

  1. #1
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    solve for x? help me complete the problem? :D

    original equation (it has a base of 4):
    2log4(x) + log4(3) = log4(x) - log4(2)

    my work so far:
    • log4(x^2) + log4(3) = log4(x) - log4(2)
    combine:
    • log4(3x^2) = log4 (x/2)


    help me finish? solve for x? gracias! (please supply your solving method and work as well, so i can understand)
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  2. #2
    Grand Panjandrum
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    Quote Originally Posted by lollilikeslife View Post
    original equation (it has a base of 4):
    2log4(x) + log4(3) = log4(x) - log4(2)

    my work so far:
    • log4(x^2) + log4(3) = log4(x) - log4(2)
    combine:
    • log4(3x^2) = log4 (x/2)


    help me finish? solve for x? gracias! (please supply your solving method and work as well, so i can understand)
    So:

    3x^2 = x/2

    etc

    CB
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  3. #3
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    e^(i*pi)'s Avatar
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    West Midlands, England
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    Quote Originally Posted by lollilikeslife View Post
    original equation (it has a base of 4):
    2log4(x) + log4(3) = log4(x) - log4(2)

    my work so far:
    • log4(x^2) + log4(3) = log4(x) - log4(2)
    combine:
    • log4(3x^2) = log4 (x/2)


    help me finish? solve for x? gracias! (please supply your solving method and work as well, so i can understand)
    You can eliminate the logs now theyre the same base: 3x^2 = \dfrac{x}{2}

    Now what do you remember about quadratic equations?
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