# Thread: solve for x? help me complete the problem? :D

1. ## solve for x? help me complete the problem? :D

original equation (it has a base of 4):
2log4(x) + log4(3) = log4(x) - log4(2)

my work so far:
• log4(x^2) + log4(3) = log4(x) - log4(2)
combine:
• log4(3x^2) = log4 (x/2)

help me finish? solve for x? gracias! (please supply your solving method and work as well, so i can understand)

2. Originally Posted by lollilikeslife
original equation (it has a base of 4):
2log4(x) + log4(3) = log4(x) - log4(2)

my work so far:
• log4(x^2) + log4(3) = log4(x) - log4(2)
combine:
• log4(3x^2) = log4 (x/2)

help me finish? solve for x? gracias! (please supply your solving method and work as well, so i can understand)
So:

$3x^2 = x/2$

etc

CB

3. Originally Posted by lollilikeslife
original equation (it has a base of 4):
2log4(x) + log4(3) = log4(x) - log4(2)

my work so far:
• log4(x^2) + log4(3) = log4(x) - log4(2)
combine:
• log4(3x^2) = log4 (x/2)

help me finish? solve for x? gracias! (please supply your solving method and work as well, so i can understand)
You can eliminate the logs now theyre the same base: $3x^2 = \dfrac{x}{2}$