Hi,

I am wondering if anyone can help me with this exercise:

Given that $\displaystyle log2=0.3$

show that $\displaystyle log5=0.7$

I tried the following approach:

$\displaystyle 0.7=0.3+0.3+\frac{1}{3}\times0.3

\\ =\log2+\log2+\log2^\frac{1}{3}$

$\displaystyle =\log(4\times\sqrt[3]{2})$

$\displaystyle \approx\log5$

Thanks for help

Gibo