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Math Help - logs

  1. #1
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    logs

    logx + log2x = log50

    Is this correct?

    3x = 50

    3/3 = 50/3

    x = 16.67 (approx.)
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  2. #2
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    It is difficult to read the post.
    Do you mean \log(x)+\log(2x)=\log(50)?
    If not, what?
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  3. #3
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    That exactly the way the question reads logx + log2x = log50 there are no brackets solve for x.
    Last edited by kiwisa; September 10th 2010 at 01:50 PM. Reason: spelling
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  4. #4
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    Please take more care in the way you post mathematics.
    You must grouping symbols. Logarithm is function and follows proper function notation.
    http://www.mathhelpforum.com/math-he...ial-19060.html
    Why not learn to post in symbols? You can use LaTeX tags.
    [tex]\log(x)[/tex] gives \log(x).
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  5. #5
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    Seriously this is the exact way it is asked :

    Solve the following equation for x.

    logx + log2x = log50

    there are no brackets or bases or anything else this is the way it has been asked, i understand what you are saying it is a function and has rules etc. but this is the way it has been asked.
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  6. #6
    Super Member bigwave's Avatar
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    assuming the given equation is

    \log(x)+\log(2x)=\log(50)

    2 log(x) = log(25)

    \log(x) = \frac{\log(25)}{2}=\log(5)

    x=5
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