I have to solve for n
A = q1 + q2 + q3/n
The answer in that back of the book has q1 + q2 + q3/a = n
how did it get that? I always end up with multiplication.
Thank you for any help, its very appreciated
You have forgotten the brackets, which are important in this.
$\displaystyle a = \dfrac{q_1 + q_2 + q_3}{n}$
$\displaystyle a \times n=q_1 + q_2 + q_3$
Remember that a*n = n*a
$\displaystyle n \times a=q_1 + q_2 + q_3$
$\displaystyle n=\dfrac{q_1 + q_2 + q_3}{a}$
If the equation was:
$\displaystyle a =q_1 + q_2 + \dfrac{ q_3}{n}$
$\displaystyle a - q_1 - q_2 =\dfrac{ q_3}{n}$
$\displaystyle a*n - q_1*n - q_2*n = q_3$
$\displaystyle n(a - q_1 - q_2) = q_3$
$\displaystyle n= \dfrac{q_3}{a - q_1 - q_2}$