I have to solve for n

A = q1 + q2 + q3/n

The answer in that back of the book has q1 + q2 + q3/a = n

how did it get that? I always end up with multiplication.

Thank you for any help, its very appreciated

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- Sep 9th 2010, 01:40 PMNecroWinterbasic algebra formula question
I have to solve for n

A = q1 + q2 + q3/n

The answer in that back of the book has q1 + q2 + q3/a = n

how did it get that? I always end up with multiplication.

Thank you for any help, its very appreciated - Sep 9th 2010, 01:57 PMPlato
I simply cannot read this posting. What does it say?

- Sep 9th 2010, 08:41 PMEducated
You have forgotten the brackets, which are important in this.

$\displaystyle a = \dfrac{q_1 + q_2 + q_3}{n}$

$\displaystyle a \times n=q_1 + q_2 + q_3$

Remember that a*n = n*a

$\displaystyle n \times a=q_1 + q_2 + q_3$

$\displaystyle n=\dfrac{q_1 + q_2 + q_3}{a}$

**If the equation was:**

$\displaystyle a =q_1 + q_2 + \dfrac{ q_3}{n}$

$\displaystyle a - q_1 - q_2 =\dfrac{ q_3}{n}$

$\displaystyle a*n - q_1*n - q_2*n = q_3$

$\displaystyle n(a - q_1 - q_2) = q_3$

$\displaystyle n= \dfrac{q_3}{a - q_1 - q_2}$