# basic algebra formula question

• September 9th 2010, 01:40 PM
NecroWinter
basic algebra formula question
I have to solve for n

A = q1 + q2 + q3/n

The answer in that back of the book has q1 + q2 + q3/a = n
how did it get that? I always end up with multiplication.

Thank you for any help, its very appreciated
• September 9th 2010, 01:57 PM
Plato
I simply cannot read this posting. What does it say?
• September 9th 2010, 08:41 PM
Educated
You have forgotten the brackets, which are important in this.

$a = \dfrac{q_1 + q_2 + q_3}{n}$

$a \times n=q_1 + q_2 + q_3$

Remember that a*n = n*a
$n \times a=q_1 + q_2 + q_3$

$n=\dfrac{q_1 + q_2 + q_3}{a}$

If the equation was:

$a =q_1 + q_2 + \dfrac{ q_3}{n}$

$a - q_1 - q_2 =\dfrac{ q_3}{n}$

$a*n - q_1*n - q_2*n = q_3$

$n(a - q_1 - q_2) = q_3$

$n= \dfrac{q_3}{a - q_1 - q_2}$