I have thought about it and see no logical way to solve it due to not seeing a relation between the m and y and n and x.

if http://filesmelt.com/dl/1346158970.png then show that xyz = 1

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- Sep 9th 2010, 10:19 AMRct33Indices based problem
I have thought about it and see no logical way to solve it due to not seeing a relation between the m and y and n and x.

if http://filesmelt.com/dl/1346158970.png then show that xyz = 1 - Sep 9th 2010, 10:51 AMPlato
This is a neat problem. From the given:

$\displaystyle m^y=a^{xy}~\&~n^x=a^{xy}$ so $\displaystyle m^x\cdot n^y=a^{2xy}$

Therefore, $\displaystyle a^{2}=(m^x\cdot n^y)^z=a^{2xyz}$.

You finish.