I am having trouble simplifying this: (-5+3i)^2
and I don't understand how to divide:
(3-4i)/(5-2i)
Any help would be great
it's just as you wrote :
$\displaystyle (-5+3i)(-5+3i ) = 25-15i-15i-9 = 16-30i $
P.S. because $\displaystyle i^2 = -1 $
and for that problem with dividing that two complex numbers ...
$\displaystyle \displaystyle \frac {3-4i}{5-2i} $
multiply now with ...
$\displaystyle \displaystyle \frac {3-4i}{5-2i} \cdot \frac {5+2i}{5+2i} = \frac {(3-4i)(5+2i)}{(5-2i)(5+2i)} $
can you continue ?