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Thread: surds

  1. #1
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    surds

    express $\displaystyle \frac{16+\frac{2\sqrt{18}}{2}}{2+\frac{6}{\sqrt{2} }} \divide 2$
    in the form $\displaystyle a+b\sqrt{2}$ where a and b are integers
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  2. #2
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    Quote Originally Posted by Punch View Post
    express $\displaystyle \frac{16+\frac{2\sqrt{18}}{2}}{2+\frac{6}{\sqrt{2} }} \divide 2$
    in the form $\displaystyle a+b\sqrt{2}$ where a and b are integers
    You can start by simplifying the denominator.

    Combine the fraction to get $\displaystyle \frac{2(\sqrt{2}+3)}{\sqrt{2}}$

    Then simplify it and you are left with $\displaystyle 2+3\sqrt{2}$
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  3. #3
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    okay... i rationalised and am stucked @ $\displaystyle \frac{14-(\frac{84}{\sqrt{2}})}{-14}$
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  4. #4
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    Yes, you're almost done, except that you did a mistake.

    I got:

    $\displaystyle \HUGE{\frac{14-\frac{42}{\sqrt{2}}}{-14}}$

    Remember that:

    $\displaystyle \frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}$
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