Am I right in saying you cannot factorise the expression x^n+1 where n if greater or equal to 3 is odd? apart from x^3 which would be (x+1)(x^2-x+1)
Follow Math Help Forum on Facebook and Google+
Originally Posted by Mukilab Am I right in saying you cannot factorise the expression x^n+1 where n if greater or equal to 3 is odd? apart from x^3 which would be (x+1)(x^2-x+1) $\displaystyle x^5 +1 = (x+1) (x^4-x^3+x^2-x+1) $ $\displaystyle x^7 +1 = (x+1) (x^6-x^5+x^4-x^3+x^2-x+1)$ $\displaystyle x^9 +1 = (x+1) (x^2-x+1) (x^6-x^3+1) $
Last edited by yeKciM; Sep 8th 2010 at 11:58 AM.
View Tag Cloud