solve

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- Sep 8th 2010, 01:50 AMPunchmodulus
solve

- Sep 8th 2010, 02:20 AMUnknown008
Square both sides:

You now need to solve this. If you can picture the graphs, you'll know that there is one solution (the most positive) when equating

So, (x-5) and (x+3) are possible roots of the polynomial above. Factoring confirms this.

You have a quadratic and two solutions. You can finish this off using the quadratic formula to get the other two remaining roots (Happy) - Sep 8th 2010, 11:43 AMSoroban
Hello, Punch!

Quote:

Square both sides: .

. .

Factor: .

. .

Wethe equation.*squared*

. . So we**must**check for extraneous roots.

But this time, all three roots are acceptable!