Did you really send this to the Clay Mathematics Institute?
I have written to scholarly professors and the Clay Mathematic Institute regarding this proposal, and all to no avail.
In reading a basic book that overviews a short list of significant mathematical theories, and one of them discusses the idea of some number other than zero being divided by zero. It clearly states that such a solution is 'undefined.' Furthermore it says if 7 / 0 = b than by cross-multiplication 0 x b = 7, and that there is no solution for that equation hence it is undefined.
I believe that there is a solution.
If 1 x 1 = 1, and 1 x 0 = 0, then I propose that 0 x 0 CANNOT = 0.
1 x 1 = 1 implies that the first number (1) is existing '1' time. 1 x 0 = 0 implies that the first number (1) is existing 'no' times, just like 1 x 5 = 5 implies that the number '1' is existing 5 times, or vice versa.
Therefore, 0 x 0 implies that '0,' or 'nothing,' is existing NO times, or '0' times. In order for zero NOT to exist, there must be SOMETHING! That is why I propose that 0 x 0 does not equal 0, but instead 0 x 0 = NON-zero (or any number other than zero).
Annnnnnnnd:
7 = nonzero so therefore 7 / 0 = 0, and through cross-multiplication, 0 x 0 = nonzero = 7.
Any other thoughts on this topic?
I cannot think of a better way to describe this concept, but I believe it to be true.
I though of an easier way to put this current discrepency; it's similar to the double-negative notion:
0 x 0 cannot = 0 because nothing not existing, or the absence of nothing, is something. 1 x 0 = 0 because something is existing no amount of times, or it is the absence of something, which is nothing. The absence of nothing is something so therefore 0 x 0 must equal anything other than 0, or non-zero if you will...