1. ## an investment

an investment yields an annual interest of $1500. If$500 more is invested and the rate is 2% less, the annual interest is $1300. What is the amount of investment and the rate of interest? 2. Sounds like a job for some simultaneous equations. Given A is the initial amount invested, r is the rate then Maybe use (1+r)A= 1500+A ...(1) and (A+500)(1+(r-2))=1300+(A+500) ...(2) Leaves you with some algebra. I may be over complicating this one, it is early morning here! 3. Hello, aeroflix! An investment yields an annual interest of$1500.
If $500 more is invested and the rate is 2% less, the annual interest is$1300.
What is the amount of investment and the rate of interest?

Let $x$ = amount invested.
Let $r$ = rate of interest.

We are told that $x$ dollars at $r$ percent yields $1500. . . Equation: . $rx \:=\:1500$ We are told that $(x+500)$ dollars at $(r-0.02)$ percent yields$1300.

. . Equation: . $(x+500)(r-0.02) \:=\:1300$

Now solve the system of equations.

You will get a quadratic equation
and must discard one of the roots.

4. thanks