Must solve by completing the square
(y^2)+3=(y/2)
thx, I really can't get this one and I'm also pretty sure there are no solutions so I don't really understand what my teacher wants
$\displaystyle \displaystyle y^2 - \frac{y}{2} = -3$
$\displaystyle \displaystyle y^2 - \frac{y}{2} + \frac{1}{16} = -3 + \frac{1}{16}
$
$\displaystyle \displaystyle \left(y - \frac{1}{4}\right)^2 = -\frac{47}{16}$
now you can say for sure that $\displaystyle y$ has no real solutions.