1. ## square root equation

I really don't get what I'm supposed to do with this problem. If someone could show me the steps, that would be great.

radical (x + 1) = x - 1

(that's supposed to be a radical sign over the x+1)

2. Originally Posted by SwissArmelle
I really don't get what I'm supposed to do with this problem. If someone could show me the steps, that would be great.

radical (x + 1) = x - 1

(that's supposed to be a radical sign over the x+1)
square both sides and solve for x. then check your solutions in the original equation to make sure none are extraneous

3. \begin{aligned}
\sqrt {x + 1} &= x - 1\\
x + 1 &= x^2 - 2x + 1\\
x^2 - 3x &= 0\\
x(x - 3) &= 0\\
x_2 &= 3
\end{aligned}

Greetings

(see why $x=0$ is refused)