# I think this belongs here??

• May 31st 2007, 03:25 PM
Gtrain
I think this belongs here??
Hey all,

im having troubles solving an equation, and this is where i have got to with it and iam stuck:

solve for y

28.68 = (15y)(15y/15+2y)^(2/3)

ive been trying to work it out for hours! i believe the answer should be between 2.9 and 5

can anyone help?
• May 31st 2007, 03:39 PM
Jhevon
Quote:

Originally Posted by Gtrain
Hey all,

im having troubles solving an equation, and this is where i have got to with it and iam stuck:

solve for y

28.68 = (15y)(15y/15+2y)^(2/3)

ive been trying to work it out for hours! i believe the answer should be between 2.9 and 5

can anyone help?

Is this what you mean? $\displaystyle 28.68 = 15y \left( \frac {15y}{15 + 2y} \right)^{ \frac {2}{3}}$
• May 31st 2007, 04:13 PM
Gtrain
yes thats it
• May 31st 2007, 05:10 PM
ThePerfectHacker
Only one solution.
$\displaystyle y\approx 15.95$
• May 31st 2007, 05:12 PM
Gtrain
hmm according to what ive got it should be between the values of 2.9 and 5??

would u mind taking me through a step to step to how you got your answer?
• May 31st 2007, 05:19 PM
Jhevon
Quote:

Originally Posted by Gtrain
hmm according to what ive got it should be between the values of 2.9 and 5??

would u mind taking me through a step to step to how you got your answer?

actually i think the answer would be between 1 and 2
• May 31st 2007, 05:21 PM
ThePerfectHacker
I made an error in the decimal point it should be,
$\displaystyle x\approx 1.595$
• May 31st 2007, 05:23 PM
Gtrain
is it possible for someone to guide me through the steps involved?
id like to be able to work out other equations like it
• May 31st 2007, 06:45 PM
ThePerfectHacker
The graph the function,

$\displaystyle f(x) = 15x \left( \frac{5x}{15+2x} \right)^{2/3}$

And the line $\displaystyle y=28.68$ and found the intersection point.
• May 31st 2007, 06:46 PM
Gtrain
AHHH ok ill try take a look at that THANKS!