Results 1 to 5 of 5

Math Help - solve for x??

  1. #1
    Newbie
    Joined
    Aug 2010
    Posts
    21

    Unhappy solve for x??



    please include your work? i just dont know how to:

    1. Make the bases on each side of the equation the same.

    2. Set the exponents equal to each other.


    thank you very much!!!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Senior Member yeKciM's Avatar
    Joined
    Jul 2010
    Posts
    456
    Quote Originally Posted by lollilikeslife View Post


    please include your work? i just dont know how to:

    1. Make the bases on each side of the equation the same.

    2. Set the exponents equal to each other.


    thank you very much!!!

     \displaystyle \sqrt {3}^{2x+4} = 9 ^{x-2}

    note that  9 = 3^2 Moderator edit: and \sqrt{3} = 3^{1/2}

    so you have

     \displaystyle {3^{\frac {2x+4}{2}}} =  3 ^{2x-4}



    so it's at the same base and now you can write that :

     \frac {2x+4}{2}} = 2x-4

    can you continue ?
    Last edited by mr fantastic; September 4th 2010 at 02:51 PM. Reason: Corrected a typo.
    Follow Math Help Forum on Facebook and Google+

  3. #3
    MHF Contributor

    Joined
    Aug 2006
    Posts
    18,605
    Thanks
    1574
    Awards
    1
    I think the previous poster misread the question.
    \left( {\sqrt 3 } \right)^{2x + 4}  = \left( {3^{\frac{1}<br />
{2}} } \right)^{2x + 4}  = 3^{x + 2}

    9^{x - 2}  = \left( {3^2 } \right)^{x - 2}  = 3^{2x - 4}

    So 3^{x + 2}  = 3^{2x - 4}

    Can you finish?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Senior Member yeKciM's Avatar
    Joined
    Jul 2010
    Posts
    456
    Quote Originally Posted by Plato View Post
    I think the previous poster misread the question.
    \left( {\sqrt 3 } \right)^{2x + 4}  = \left( {3^{\frac{1}<br />
{2}} } \right)^{2x + 4}  = 3^{x + 2}

    9^{x - 2}  = \left( {3^2 } \right)^{x - 2}  = 3^{2x - 4}

    So 3^{x + 2}  = 3^{2x - 4}

    Can you finish?
    we wrote the same thing i didn't misread anything
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Flow Master
    mr fantastic's Avatar
    Joined
    Dec 2007
    From
    Zeitgeist
    Posts
    16,948
    Thanks
    5
    Quote Originally Posted by yeKciM View Post
    we wrote the same thing i didn't misread anything
    The expression you posted:
    Quote Originally Posted by yeKciM View Post
     \displaystyle \sqrt {3^{2x+4}} = 9 ^{x-2}
    [snip]
    suggested otherwise. I assume by accident you were square rooting everything rather than just the 3. I have edited your original post.
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. need to solve summation equation to solve sum(x2)
    Posted in the Statistics Forum
    Replies: 2
    Last Post: July 16th 2010, 10:29 PM
  2. Replies: 1
    Last Post: June 9th 2009, 10:37 PM
  3. how do I solve this?
    Posted in the Calculus Forum
    Replies: 5
    Last Post: January 22nd 2009, 06:21 PM
  4. How could i solve?
    Posted in the Algebra Forum
    Replies: 2
    Last Post: January 2nd 2009, 02:18 PM
  5. Solve for x
    Posted in the Trigonometry Forum
    Replies: 3
    Last Post: January 1st 2009, 12:33 PM

Search Tags


/mathhelpforum @mathhelpforum