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Math Help - Check answers of rational expressions

  1. #1
    Newbie
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    Sep 2010
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    Check answers of rational expressions

    Hi,

    I am in an Algebra II class. I already took it years ago, but I am taking it again as a refresher. I have done two problems that I uploaded for this community to check to see if I have the right answer. I wrote out the whole equation. This will probably be very easy for the members here.

    1.) This is a subtraction and simplifying of a rational expression.
    http://i53.tinypic.com/24nh2zn.jpg

    2.) This is a find the domain problem...
    http://i51.tinypic.com/5p0eog.jpg
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  2. #2
    Senior Member yeKciM's Avatar
    Joined
    Jul 2010
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    Quote Originally Posted by dudeman893 View Post
    Hi,

    I am in an Algebra II class. I already took it years ago, but I am taking it again as a refresher. I have done two problems that I uploaded for this community to check to see if I have the right answer. I wrote out the whole equation. This will probably be very easy for the members here.

    1.) This is a subtraction and simplifying of a rational expression.
    http://i53.tinypic.com/24nh2zn.jpg

    2.) This is a find the domain problem...
    http://i51.tinypic.com/5p0eog.jpg



    for the first one

     \displaystyle \frac {8xy}{x^2-y^2} - \frac  {x-y}{x+y}

     \displaystyle \frac {8xy}{(x-y)(x+y)} - \frac  {x-y}{x+y}

     \displaystyle \frac {8xy - (x-y)(x-y)}{(x-y)(x+y)}

    ........... and so on


    for the secon one

     \displaystyle \frac {6}{x(x-7)}

     x(x-7) =0 \Rightarrow x_1=0 ; x_2 = 7

    so it's  x \in (-\infty , 0) \cup (0 , 7 )  \cup ( 7, +\infty)

    that means that function is not defined just for x=0 , and x=7
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