# Math Help - Solving log equation

1. ## Solving log equation

How to find x in this equation:

2. Originally Posted by Garas
How to find x in this equation:
There is no solution.

$\log_{15}(2/9)=\log_3x\implies x=3^{\log_{15}(2/9)}$

But $\log_5(1-3^{\log_{15}(2/9)}) \ne \log_{15}(2/9)$

3. Those are two separate equations, $log_{15}\frac{2}{9}= log_3 x$ and $log_3 x= log_5(1- x)$. As undefined said, there is no value of x that satifies both. Was one of those "=" supposed to be "-" or "+"?

4. no, that math problem was in a test for the entrance to the college