# Thread: tricky find the numbers

1. ## tricky find the numbers

the sum of the squares of 2 numbers is 5/18. The sum of 6 times the smaller number and 4 times the larger number is 3. What are the numbers?

2. Use simultaneous equation:

Lets call the first number x and the second y

$\displaystyle x^2 + y^2 = \frac{5}{18}$

$\displaystyle 6x + 4y = 3$

Now can you carry on?

3. yes i know tht equation but my problem is

how to simplify this???

(3-6x/4)^2

4. Originally Posted by aeroflix
yes i know tht equation but my problem is

how to simplify this???

(3-6x/4)^2
Where has this come from? What equation is it meant to be? Please show your working in full so that it can be understood if you need help with it. (And perhaps doing this will help you clarify your thoughts on the question, and you might even see how to solve it).

5. this is the way i do it... i was stucked at the red box... is my solution correct?

6. Expand, then re-arrange into a quadratic equation.

7. ## a graphical solution

Originally Posted by aeroflix
this is the way i do it... i was stucked at the red box... is my solution correct?
when solutions are difficult to solve one must always take the help of graphs because graphs portray what exactly is going on. see attachment:

8. $\displaystyle \left(\frac{3- 4y}{6}\right)^2= \frac{(3- 4y)^2}{6^2}= \frac{9- 24y+ 16y^2}{36}$

9. thanks guyz!!! the simplication of that red box help me ))) thanks guyz! your the best