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Math Help - I need help with these rational expressions

  1. #1
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    Exclamation I need help with these rational expressions

    Okay so these are the 4 rational expressions that I need step by step answers on:

    1. √(24a^4b^5c^9)

    2. 2√(50) + 13√(200)

    3. (rewrite the radical expression in simplier radical form) - I have no idea what that means. 3√(5) (5√(3) + 2√(12))

    4. (Solve the equation using your knowledge of radicals) - does it mean to just solve the equation? √(x + 12) = x

    sorry it's a lot, these are the four I didn't understand.
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  2. #2
    Super Member bigwave's Avatar
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    take out the squares

    is #1 this??

    \sqrt{24a^{4}b^{5}c^{9}} is just take the squares out of it

    for #2

    2\sqrt{50} + 13\sqrt{200} \Rightarrow 2\sqrt{25}\sqrt{2} + 13\sqrt{100}\sqrt{2}

    you can probably see the rest of this..
    Last edited by bigwave; September 2nd 2010 at 12:58 PM. Reason: added step
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  3. #3
    MHF Contributor undefined's Avatar
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    Quote Originally Posted by jenbones View Post
    Okay so these are the 4 rational expressions that I need step by step answers on:

    1. √(24a^4b^5c^9)

    2. 2√(50) + 13√(200)

    3. (rewrite the radical expression in simplier radical form) - I have no idea what that means. 3√(5) (5√(3) + 2√(12))

    4. (Solve the equation using your knowledge of radicals) - does it mean to just solve the equation? √(x + 12) = x

    sorry it's a lot, these are the four I didn't understand.
    I understand you want step by step answers but this is not a homework service.

    The general rule you will apply in questions 1 and 2 is: \sqrt{a^2b}=|a|\sqrt{b}

    For 3: \sqrt{a}\cdot\sqrt{b} = \sqrt{ab} (for a and b non-negative)

    For 4: If you square both sides you will get a quadratic equation. At the end you should make sure \displaystyle x \ge 0 and x + 12 \ge 0 hold.
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  4. #4
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    Quote Originally Posted by bigwave View Post
    is #1 this??

    \sqrt{24a^{4}b^{5}c^{9}} is just take the squares out of it

    for #2

    2\sqrt{50} + 13\sqrt{200} \Rightarrow 2\sqrt{25}\sqrt{2} + 13\sqrt{100}\sqrt{2}

    you can probably see the rest of this..
    yes number one is correct
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  5. #5
    Super Member bigwave's Avatar
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    \sqrt{24{a}^{4}b^{5}c^{9}}<br />
\Rightarrow<br />
\sqrt{4}\sqrt{6}\sqrt{a^4}\sqrt{b^4}\sqrt{b}\sqrt{  c^8}\sqrt{c}<br />
\Rightarrow<br />
2a^{2}b^{2}c^{4}\sqrt{6bc}<br />

    there are other forms of this if you want fractional exponents.

    #2  \sqrt{25}\sqrt{2} + 13\sqrt{100}\sqrt{2}<br />
\Rightarrow<br />
10\sqrt{2}+130\sqrt{2}<br />
\Rightarrow<br />
140\sqrt{2}
    Last edited by bigwave; September 2nd 2010 at 03:59 PM. Reason: added step
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