How is this decomposed?
$\displaystyle \frac{x^4+1}{x^3(x^2+4)}$
The answer doesn't need to be solved for A,B,C,etc
Hello, Mike9182!
How is this decomposed? . $\displaystyle \dfrac{x^4+1}{x^3(x^2+4)}$
. . $\displaystyle \displaystyle \frac{x^4+1}{x^3(x^2+4)} \;=\;\frac{A}{x} + \frac{B}{x^2} + \frac{C}{x^3} + \frac{Dx+E}{x^2+4}$
You should get: .$\displaystyle A = \text{-}\frac{1}{16},\; B \:=\:0,\; C \:=\:\frac{1}{4},\; D \:=\:\frac{17}{16},\; E \:=\:0 $