I need step by step help on solving this equation:
4x^2 - 15x = 3
$\displaystyle \displaystyle 4x^2 - 15x = 3 $
$\displaystyle \displaystyle 4x^2 - 15x -3= 0 $
by the quadartic formula
$\displaystyle \displaystyle ax^2 + bx +c= 0 \implies x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$
$\displaystyle \displaystyle 4x^2 - 15x -3= 0 \implies x = \frac{-(-15)\pm\sqrt{(-15)^2-4\times 4\times (-3)}}{2\times 4}$
You got it from here?
given the quadratic formula with all variables filled in, you simply simplify down (notice the pun there)
$\displaystyle x = \frac{-(-15)\pm\sqrt{(-15)^2-4\times 4\times (-3)}}{2\times 4}$
$\displaystyle x = \frac{15\pm\sqrt{225-48}}{8}$
$\displaystyle x = \frac{15\pm\sqrt{177}}{8}$
Using order of operations, of course.