Okay so once again I get confused on the first step. I could really use a step by step answer on how to simplify this expression: (4x^2 - 20x + 3) / (2x + 1) + (2x^2 - 25x - 27) / (4x + 2)
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You have $\displaystyle \frac{4x^2 - 20x + 3}{2x + 1} + \frac{2x^2 - 25x - 27}{4x + 2}$ Did you not notice that 4x+ 2= 2(2x+ 1)? That helps a lot doesn't it?
Originally Posted by HallsofIvy You have $\displaystyle \frac{4x^2 - 20x + 3}{2x + 1} + \frac{2x^2 - 25x - 27}{4x + 2}$ Did you not notice that 4x+ 2= 2(2x+ 1)? That helps a lot doesn't it? could you show me step by step on how to simplify it?
Originally Posted by jenbones Okay so once again I get confused on the first step. I could really use a step by step answer on how to simplify this expression: (4x^2 - 20x + 3) / (2x + 1) + (2x^2 - 25x - 27) / (4x + 2) $\displaystyle \displaystyle\frac{4x^2-20x+3}{2x+1}+\frac{2x^2-25x-27}{4x+2}=\frac{2\left(4x^2-20x+3\right)}{2(2x+1)}+\frac{2x^2-25x-27}{2(2x+1)}$ $\displaystyle =\displaystyle\frac{8x^2-40x+6+2x^2-25x-27}{2(2x+1)}=\frac{10x^2-65x-21}{2(2x+1)}$