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Math Help - Rearrange the formula.

  1. #1
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    Rearrange the formula.

    The formula is F= 35e^-0.7p

    make p the subject.

    Thanks in advance I am not sure where to start.

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  2. #2
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    F = 35e^{-0.7p}

    \frac{F}{35} = e^{-0.7p}

    \ln{\left(\frac{F}{35}\right)} = -0.7p

    -\frac{10\ln{\left(\frac{F}{35}\right)}}{7}.
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  3. #3
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    You "undo" what has been done to p.

    35e^{-0.7p}= F
    The last thing done on the left is "multiply by 35" so the first thing you do to solve for p is divide both sides by 35:
    35e^{-0.7p}/35= e^{-0.7p}= \frac{F}{35}

    Now, we have an exponential function (e to a power). The reverse of that is the "natural logarithm". Take the logarithm of both sides:
    ln(e^{-0.7p})= -0.7p= ln(\frac{F}{35})

    Finally, p is multiplied by -0.7. Divide both sides by -0.7:
    -0.7p/(-0.7)= p= -\frac{ln(\frac{F}{35})}{0.7}
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