Results 1 to 5 of 5

Math Help - solving for x

  1. #1
    Newbie
    Joined
    Aug 2010
    Posts
    4

    solving for x

    Hi! My problem is:

    (x)(2^x) = 1

    How do I solve for x? I tried using logarithms like this:

    log(x) + x*log(2) = log(1)

    but then I have the first x stuck inside a log. Help please!
    Follow Math Help Forum on Facebook and Google+

  2. #2
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,234
    Thanks
    27
    What you have tried is not correct.

    You cannot solve this using conventional algebra.

    You should try a numerical method.

    I get x\approx 0.64
    Follow Math Help Forum on Facebook and Google+

  3. #3
    Newbie
    Joined
    Aug 2010
    Posts
    4
    Do you mean I should just use my graphing calculator? I get about the same when I do that. Just out of curiosity, what kind of algebra would you use to do this?
    Follow Math Help Forum on Facebook and Google+

  4. #4
    Master Of Puppets
    pickslides's Avatar
    Joined
    Sep 2008
    From
    Melbourne
    Posts
    5,234
    Thanks
    27
    The conventional algebra I speak of is using inverse operations to isolate x.

    The other types of algebra (i.e. abstract algebra) aren't related to achieving this result.
    Follow Math Help Forum on Facebook and Google+

  5. #5
    Newbie
    Joined
    Aug 2010
    Posts
    4
    OK, thanks!
    Follow Math Help Forum on Facebook and Google+

Similar Math Help Forum Discussions

  1. I need help solving for x
    Posted in the Pre-Calculus Forum
    Replies: 9
    Last Post: July 8th 2010, 02:14 PM
  2. solving for x.
    Posted in the Algebra Forum
    Replies: 11
    Last Post: September 11th 2009, 07:20 PM
  3. Help with solving a log
    Posted in the Algebra Forum
    Replies: 1
    Last Post: June 30th 2008, 01:32 PM
  4. solving cos.
    Posted in the Trigonometry Forum
    Replies: 1
    Last Post: November 25th 2007, 09:17 AM
  5. Replies: 3
    Last Post: October 11th 2006, 09:15 PM

Search Tags


/mathhelpforum @mathhelpforum