Hi! My problem is: (x)(2^x) = 1 How do I solve for x? I tried using logarithms like this: log(x) + x*log(2) = log(1) but then I have the first x stuck inside a log. Help please!
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What you have tried is not correct. You cannot solve this using conventional algebra. You should try a numerical method. I get $\displaystyle x\approx 0.64$
Do you mean I should just use my graphing calculator? I get about the same when I do that. Just out of curiosity, what kind of algebra would you use to do this?
The conventional algebra I speak of is using inverse operations to isolate x. The other types of algebra (i.e. abstract algebra) aren't related to achieving this result.
OK, thanks!
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