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**aussiekid90** The question is: Sketch a polynomial function of degree 3 that has x-intercepts 1, 2, and 3, has a y intercept of 6, and passes through the point (-1,25). Can you actually have the graph you just drew?

So, i tried making the formula for the function and i started out with the base (x-1)(x-2)(x-3) to get the x intercepts. Then i added 6 to the end to bump the function up to have a y intercept of 6. Finally, i plugged in (-1,25) to the function in order to find the leading coefficiant of a(x-1)(x-2)(x-3)+6=f(x)

I then solve for A and it comes out something like .7196666 repeating. I check the graph F(x)=.719666666(x-1)(x-2)(x-3)+6 and it looks nothing like its supposed to. Please Help. THANKS!!!!