Polynomial Help Please Urgent!!!

The question is: Sketch a polynomial function of degree 3 that has x-intercepts 1, 2, and 3, has a y intercept of 6, and passes through the point (-1,25). Can you actually have the graph you just drew?

So, i tried making the formula for the function and i started out with the base (x-1)(x-2)(x-3) to get the x intercepts. Then i added 6 to the end to bump the function up to have a y intercept of 6. Finally, i plugged in (-1,25) to the function in order to find the leading coefficiant of a(x-1)(x-2)(x-3)+6=f(x)

I then solve for A and it comes out something like .7196666 repeating. I check the graph F(x)=.719666666(x-1)(x-2)(x-3)+6 and it looks nothing like its supposed to. Please Help. THANKS!!!!

...a push in the right direction

Hi Aussiekid90:

The general form of a __cubic polynomial__ function is f(x)=ax^3+bx^2+cx+d. Recall that a "*polynomial of degree n"* is, by definition, __the sum of all non-negative integral powers of __*x* (meaning with integer exponents), having "greatest" degree, n, and all coefficients __real__.

Now, you are given that each of (1,0),(2,0),(3,0),(0,6)and(-1,25)is a solution of the above noted function. That is a *mountain* of information. First, the value of constant *d* is a gift. Next, using said mountain, write two equations of the form 0 = ..., such that the terms comprising the "..." contain only *a*, *b*, *c* and *6* (woops, I slipped!). Having done so, you will likely observe a pretty nifty occurance, should you happen to possess sufficient insight to consider adding these equations, thus constructing yet another in the process. :)

I am confident that, having arrived at the juncture marked by the smiley above, the rest will just "*sorta* *fizzle all together"* (in the words of a really cool dude who answers to the name "Neil Young").

Happy function hunting,

Regards,

Rich B.