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Math Help - numbers in brackets

  1. #1
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    numbers in brackets

    Hi;
    The problen is factor y^2-5y+6.

    now I know how to factor this to (y-2)(y-3).

    my issue is I could reverse the position of the 2 and the 3 without harmimg the outcome is that correct?

    thanks.
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  2. #2
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    Yes that will be fine.

    Remember that A\times B \equiv B \times A.

    Therefore (y-2)(y-3)\equiv (y-3)(y-2).
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  3. #3
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    You can only reverse it if the signs are the same and the number before the y is the same, and in this equation, yes you can.

    If you had (y+2)(y-3) then you would not be able to switch the 2 & 3 because the signs are different (unless you moved the signs as well).
    Also, if you had (2y-2)(y-3) then you would not be able to switch them because the number before the y is different.

    But in your case, the signs and number before the y is the same, so you can reverse the positions of the 2 and 3.
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  4. #4
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    So the same for this as well.
    x^2+x-12 factors to (x+4)(x-3) or (x-3)(x+4) again same principle applies.

    thanks for the help.
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  5. #5
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    Correct.
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