Okay, so I used the quadratic formula to solve the following equation:

$x^2 - 6x + \frac{226}{25} = 0$

I came up with 3 +/- i after reducing. My question is, if the quadratic formula applies to this equation, did I get the correct answer?

2. Originally Posted by wrongnmbr
Okay, so I used the quadratic formula to solve the following equation:

$x^2 - 6x + \frac{226}{25} = 0$

I came up with 3 +/- i after reducing. My question is, if the quadratic formula applies to this equation, did I get the correct answer?
You should have a different co-efficient for $i$

$x=\frac{-b \pm i \sqrt{4ac-b^2}}{2a}$
I got $x=3\pm\frac{1}{5}i.$
4. Using $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ I get $x = 6 \pm \frac{2}{5}i$ which is the same result as CuriosityCabinet's once simplified. The quadratic formula applies to all quadratics, you probably just made a minor numerical error somewhere.