Can someone please help me.....I was given these problems to fix the errors!
x3/2 = 27/64, so x = ¾ and ln(12 + x) = (ln 12)(ln x)
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You have ln(12+x)=ln12+lnx Therefore ln(12+x)=ln12x if you put e to both logs you get 12+x=12x---->12=11x--->x=12/11
I would normally be more wordy and explain each step but I see they don't do that here.
Originally Posted by radams33 .....I was given these problems to fix the errors!
ln(12 + x) = (ln 12)(ln x) Assuming this is an error?
It should be
Yes I was given both of those equations to find the errors.
Thank you everyone!
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