I have done i. With ii I cannot get an equation that does not include x as a part of the coefficient of x. The answer in the book is px=1-q(y/x). Compared to y=mx+c what are the equivalents of m and c?
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Divide by x; Move the qy/x around; Here, you can take the Y as being x and X as being y/x. This gives: You can put it in the form Y = mX + c now?
Yes, I suppose I would plot x against y/x. I don't think the books answer is quite what is asked for. The left side needs to be divided by p and the right side multiplied by p.
Originally Posted by Stuck Man Yes, I suppose I would plot x against y/x. I don't think the books answer is quite what is asked for. The left side needs to be divided by p and the right side multiplied by p. Not quite... when you divide a side by p, you need to divide both sides by p. So, m becomes -q/p and c becomes 1/p
Thats what I was thinking of. Thanks.
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