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Math Help - Straight line graph

  1. #1
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    Straight line graph

    I have done i. With ii I cannot get an equation that does not include x as a part of the coefficient of x. The answer in the book is px=1-q(y/x). Compared to y=mx+c what are the equivalents of m and c?
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  2. #2
    MHF Contributor Unknown008's Avatar
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    px^2 + qy = x

    Divide by x;

    px + \frac{qy}{x} = 1

    Move the qy/x around;

    px = 1 - \frac{qy}{x}

    Here, you can take the Y as being x and X as being y/x.

    This gives:

    pY = 1 - qX

    You can put it in the form Y = mX + c now?
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  3. #3
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    Yes, I suppose I would plot x against y/x.

    I don't think the books answer is quite what is asked for. The left side needs to be divided by p and the right side multiplied by p.
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  4. #4
    MHF Contributor Unknown008's Avatar
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    Quote Originally Posted by Stuck Man View Post
    Yes, I suppose I would plot x against y/x.

    I don't think the books answer is quite what is asked for. The left side needs to be divided by p and the right side multiplied by p.
    Not quite... when you divide a side by p, you need to divide both sides by p.

    \frac{pY}{p} = \frac{1-qX}{p}

    Y= \frac{1}{p}-\frac{q}{p}X

    So, m becomes -q/p and c becomes 1/p
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  5. #5
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    Thats what I was thinking of. Thanks.
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