soybean is 16% protien . corn is 8% protien. how many pounds of each should be mixed together in order to get 320 lb mixture that is 12% protien.
how many pounds of soybean
how many pounds of corn
Hi mafai44,
Let x = pounds of soybeans needed.
Let y = pounds of corn needed.
[1] x + y = 320
[2] .16x + .08y = .12(320)
From [1] y = 320 - x
[2].16x + .08(320 - x) = .12(320)
16x + 8(320 - x) = 12(320)
16x + 2560 - 8x = 3840
8x = 1280
x = 160 pounds of soybeans needed
From [1] y = 320 - 160 = 160 pounds of corn needed