# finding power of

• August 15th 2010, 05:25 AM
podlium
finding power of
Hi,

one simple question :) (to someone who knows), i am stuck,
how to get n from equation, if i know what x and y are:

$x = y^n$
• August 15th 2010, 05:36 AM
Prove It
You need to use logarithms...

$x = y^n$

$\ln{x} = \ln{(y^n)}$

$\ln{x} = n\ln{y}$

$n = \frac{\ln{x}}{\ln{y}}$.
• August 15th 2010, 05:49 AM
podlium
TNX :) , i thought it has something to do with logarithms. I really appreciate it
• August 15th 2010, 06:10 AM
Prove It
Of course, it doesn't have to be the natural logarithm. It can be the logarithm of any base... I just always use natural logarithms because they're the most often used in practice...